losikid, I'm interested to see how this develops.
I would suggest working out your desired wheelspeed in RPM, and find the no load speed of the motor you choose to use, then calculate the gear ratio from that. Next step is to consider how to achieve the rquired ratio.
Wheel speed is easy enough to calculate.
1/ Start with miles per hour (MPH) that you think will work, divided by 60 equals miles per minute, multiplied by 5,280 equals feet per minute. For example 3MPH = 264 fpm.
2/ Put a mark on a tire and roll it along the floor for exactly one revolution, measure the distance it travelled in feet. (eg: 1 foot 6 inches = 1.5 feet.) For example a 7" diameter tire travels about 1.8 feet per revolution.
3/ Divide the result of 1/ by the result of 2/ should give wheel speed in RPM. For example 264 / 1.8 = 146 RPM.
4/ A little search on this forum should yeald a no-load RPM for the motor you have in mind. A 55T 540 can motor on 2 cell LiPo makes roughly 7,000 to 8,000 RPM, but don't quote me on that!
5/ Divide 4/ (motor RPM) by 3/ (wheel RPM) will give the gear ratio you require. In my example 8,000 / 146 = 54.8, so that means you want 54.8 : 1 gear ratio.
These are very simple calculations you can do with the calculator function in a mobile phone, or just pen and paper. I think it is likely that you will need more than one stage of gear reduction to achieve the right ratio, simply because, with a 10 tooth pinion, you would need a 548 tooth spur (in my example above) and that's a huge spur gear! It could easily be done with two stages though.
Hope this helps.
Cheers.