Vanquish 6 inch light bar help

[jrhkubota]

Hello fellow scalers. I am looking to get a 6 inch light bar from vanquish it says it needs 11.1 volts. but I was wondering if I can I run it on 2, 9 volt batteries which would equal 18 volts or is that too much. Any help is appreciated. Thanks.

[Meatwad]

It says 11.1 so 18 is too much. Although it may work, I'm sure no one will recommend doing it.

Either take a split from your pack (if 3s), get a dedicated 3s pack for it or use a cc bec on those two 9v batteries that's programmed to spit out 11.1v.

[jrhkubota]

Ok thanks man I'll see what I can do.

[WesTX]

You can get a cheap 3S battery, this is the one I just got to run my light bar:

http://www.amazon.com/gp/product/B00...?ie=UTF8&psc=1

Wes

[MCW24]

just buy a cheap small three cell

[Awesome-Sauce RC]

9v batteries are not really great for outputting a good constant current, they would not last long powering the lightbar before they ran out.

as mentioned a small 3s with a good discharge rate would keep it running better and longer than the 9v option.


tony

[jrhkubota]

Ok thanks guys I was thinking that would be better than regular batteries. I'm also getting a roof rack so I could just stuff a small 3s on the roof rack.

[MCW24]

i use velcro underneath the body keeps the battery out of harms way

[nuhobby]

Originally Posted by jrhkubota

Hello fellow scalers. I am looking to get a 6 inch light bar from vanquish it says it needs 11.1 volts. but I was wondering if I can I run it on 2, 9 volt batteries which would equal 18 volts or is that too much. Any help is appreciated. Thanks.

Works fine with two 9v batteries. Cheap, light weight and don't have to worry about running lipo too low. I'm running double 9v's on 6" hand made led strip bar now with no problems. getting about 7-8 hrs constant. Use ohms law LED Resistor Calculator to be safe. Calculating an LED resistor value:

The 5050 white waterproof SMD used in your Vanquish light bar already has integrated resisters in it, one resister for every 3 led group.
the construction of 5050 is the same:3LED+1R, but SMD5050 is 3 channel output


LED resistor circuit An LED must have a resistor connected in series to limit the current through the LED, otherwise it will burn out almost instantly.

The resistor value, R is given by:

R = (VS - VL) / I

VS = supply voltage
VL = LED voltage (usually 2V, but 4V for blue and white LEDs)
I = LED current (e.g. 10mA = 0.01A, or 20mA = 0.02A)
Make sure the LED current you choose is less than the maximum permitted and convert the current to amps (A) so the calculation will give the resistor value in ohms (ohm).
To convert mA to A divide the current in mA by 1000 because 1mA = 0.001A.

If the calculated value is not available choose the nearest standard resistor value which is greater, so that the current will be a little less than you chose. In fact you may wish to choose a greater resistor value to reduce the current (to increase battery life for example) but this will make the LED less bright.

For example
If the supply voltage VS = 9V, and you have a red LED (VL = 2V), requiring a current I = 20mA = 0.020A,
R = (9V - 2V) / 0.02A = 350ohm, so choose 390ohm (the nearest standard value which is greater).

Working out the LED resistor formula using Ohm’s law
Ohm’s law says that the resistance of the resistor, R = V/I, where:
V = voltage across the resistor (= VS - VL in this case)
I = the current through the resistor

So R = (VS - VL) / I

Construction of Flexible LED strips:

the construction of the SMD led strips is as following:

take SMD3528, 60led/m for example:

first of all, every "3 LED and 1 resistor" is in series connection, if we call it one group,

there is 20 groups on this LED strips,(60LED/3=20)

the connection of each group is in parallel circuit.

so, each 3 LED can be cutted, because, the connection between another 3 LEDS is parallel, cutting will cause not affects to another group,

and if one LED among the 3 LEDs breaks, all 3 LEDs can not light on, because the 3 LEDS are in series conections.

we call this model as: 3LED+1R.



the electricity currect of each LED is 0.02A, so, the electricity of each group(3LED+1R) is 0.02A,

there is total 20 groups(60LED/3=20), so, the electricity of each Meter( 60LED) is 0.02*20=0.4A,

the driven voltage is 12V,

so, the power comsuption of each meter( 60LED) is: 12*0.4=4.8W.



the construction of 5050 is the same:3LED+1R, but SMD5050 is 3 channel output,

take SMD5050, 60led/m for example:

the electricity of each 5050 will be: 60/3*0.02*3=1.2A, the driving voltage is 12V,

so, the power comsuption of each meter of 5050( 60led/m ) is: 12*1.2=14.4W.

Hope this helps and is not too confusing John

[JOver]

I run my light bar off a DC/DC converter, and ran off a cheap BEC. It's adjustable with a 5v input I can crank out a max of 30+- volts! It's working great and have this set up in two trucks. One is running a light bar, and 6 LEDs with a plug for a trailer. The trailer has 6 LEs on it. So far this is the cheapest and easily expandable option I've found.

[nuhobby]

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